(x-3)^2-(2x-4)^2/3x-1

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Solution for (x-3)^2-(2x-4)^2/3x-1 equation:


x in (-oo:+oo)

(x-3)^2-(x*(((2*x-4)^2)/3))-1 = 0

(x-3)^2+(-1*x*(2*x-4)^2)/3-1 = 0

(3*(x-3)^2)/3+(-1*x*(2*x-4)^2)/3+(-1*3)/3 = 0

3*(x-3)^2-1*x*(2*x-4)^2-1*3 = 0

19*x^2-4*x^3-34*x-3+27 = 0

19*x^2-4*x^3-34*x+24 = 0

19*x^2-4*x^3-34*x+24 = 0

19*x^2-4*x^3-34*x+24 = 0

{ 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 8, -8, 12, -12, 24, -24 }

1

x = 1

19*x^2-4*x^3-34*x+24 = 5

1

-1

x = -1

19*x^2-4*x^3-34*x+24 = 81

-1

2

x = 2

19*x^2-4*x^3-34*x+24 = 0

2

x-2

11*x-4*x^2-12

19*x^2-4*x^3-34*x+24

x-2

4*x^3-8*x^2

11*x^2-34*x+24

22*x-11*x^2

24-12*x

12*x-24

0

11*x-4*x^2-12 = 0

DELTA = 11^2-(-12*(-4)*4)

DELTA = -71

DELTA < 0

x in { 2}

x-2 = 0

(x-2)/3 = 0

(x-2)/3 = 0 // * 3

x-2 = 0

x-2 = 0 // + 2

x = 2

x = 2

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